# Surface Integral to Volume Integral Conversion Using the Divergence Theorem

The closed surface integral $$\oint\_S x \times d S$$ is always zero because the curl of the position vector ( $$\nabla \times x$$ ) is always zero, a mathematical result that is physically consistent with vectors either being individually zero or cancelling each other out due to a surface's symmetry.

### :clapper:Compare how vectors behave on a sphere and a cylinder

> A zero result for a surface integral can be achieved either because all individual vectors are zero (as seen on the sphere), or because non-zero vectors cancel each other out due to symmetry (as seen on the cylinder).

{% embed url="<https://youtu.be/W27TrSB9KB0>" %}

### :pen\_ballpoint:Mathematical Proof

{% embed url="<https://viadean.notion.site/Surface-Integral-to-Volume-Integral-Conversion-Using-the-Divergence-Theorem-2561ae7b9a3280508400eb8eab73b068?source=copy_link>" %}
