🧄Surface Integral to Volume Integral Conversion Using the Divergence Theorem

The closed surface integral Sx×dS\oint_S x \times d S is always zero because the curl of the position vector ( ×x\nabla \times x ) is always zero, a mathematical result that is physically consistent with vectors either being individually zero or cancelling each other out due to a surface's symmetry.

🎬Compare how vectors behave on a sphere and a cylinder

A zero result for a surface integral can be achieved either because all individual vectors are zero (as seen on the sphere), or because non-zero vectors cancel each other out due to symmetry (as seen on the cylinder).

🖊️Mathematical Proof

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